The Brackets!

Saturday, May 8, 2021

The Ladder of Art -- Week #104 ("London")



Last Week's Results
1. Kiefer: 6
1. Chase: 6

3. H. Rousseau: 5
3. Ter Borch: 5

5. Cuyp: 3
5. Corot: 3
7. Poussin: 1


This Week's Contest


Alfred Wallis
1855 - 1942
British

Tournament Record: Tied for 251st. Lost to Warhol, beat Wadsworth, lost to Vlaminck. 14 votes for, 16 against (.467).



Jan Siberechts
1627 - 1703
Dutch; worked in Britain

Tournament Record: Tied for 251st. Beat Sickert, lost to Sheeler and Severini. 14 votes for, 16 against (.467).




Pieter De Hooch
1629 - 1684
Dutch

Tournament Record: Tied for 253rd. Beat van Honthorst and Homer (who recovered to place 7th!), lost to Varo, beat Hobbema, lost a rematch to Homer. 32 votes for, 37 against (.455).



Sir Edward Burne-Jones
1833 - 1898
British

Tournament Record: Placed 254th. Lost to Buren and Jan Bruegel the Elder. 13 votes for, 15 against (.464). Highest ranked 0-2 artist.




Henri Rousseau
1844 - 1910
French

Tournament Record: Tied for 255th. Beat Roubiliac, tied with Rubens, beat Sisley and Rossetti, lost to Sargent and Rivera. 32 votes for, 37 against (.464).

  • Tied for Third in Week #103.


Gerard Ter Borch
1617 - 1681
Dutch

Tournament Record: Tied for 257th. Lost to Teniers, tied with Tanguy, beat Nolde, lost to Terbrugghen. 19 votes for, 22 against (.463).

  • Tied for Third, Week #103.



Ferdinand Hodler
1853 - 1918
Swiss

Tournament Record: Placed 275th. Defeated Hans Hofmann, tied with Hockney, beat Goya, Lost to Hiroshige and Homer. 28 votes for, 34 against (.452).

  • Placed First, Week #94.
  • Placed First, Week #96. 
  • Placed First, Week #98.
  • Tied for First, Week #100.
  • Placed First, Week #102.

 

Cast up to four votes in the comments by Saturday morning!

8 comments:

  1. Hodler, and then I like the rest about equally so I will vote for none.

    ReplyDelete
  2. Hodler, Hooch, Rousseau, and Siberechts.

    ReplyDelete
  3. Rousseau, De Hooch, Ter Borch, and Hodler.

    ReplyDelete
  4. Rousseau, Burne-Jones, de Hooch, Ter Borch.

    ReplyDelete
  5. Hodler, De Hooch, Ter Borch, and Siberechts.

    ReplyDelete
  6. Oh hi! Susan, back in early May, said "VOTES: Jan Siberechts, Pieter De Hooch, Henri Rousseau & HODLER."

    ReplyDelete
  7. I'll say Hodler and Wallis, for myself.

    ReplyDelete

Voting in the Infinite Art Tournament? Awesome. And, please be aware that purely anonymous votes are not counted. You don't need to log in or use your real name, but you must identify yourself in some fashion for your vote to count.