The Brackets!

Tuesday, June 9, 2015

The Infinite Art Tournament, Round 3: Benton v. Lotto!

Thomas Hart Benton
1889 - 1975
American

Finished First in Phase 1, Flight 10, with a voting score of .818.
Tied for Second in Phase 2, Flight 2, with a voting score of .364.
Survived the Phase 2 Tiebreaker.
Beat John Robert Cozens easily in Round 1.
Beat Richard Long easily in Round 2.








Lorenzo Lotto
1480 - 1556
Venetian

Defeated abstract American Morris Louis in Round 1.
Nudged Lorenzo Monaco in Round 2 by a two-vote swing. YOUR VOTE COUNTS!!!









Vote for the artist of your choice in the comments, or any other way that works for you. Commentary and links to additional work are welcome. Polls open for at least one month past posting.

14 comments:

  1. Benton. Lotto seems kind of blah in comparison.

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  2. I feel like this is a pretty weak 3rd round match, but, then again, I seem less keen on Benton than everyone else. I'll go with Lotto and whomever they face next round.

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  3. I feel Benton is far superior!

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  4. Down with surly Venetian men in their silly hats! Thomas Hart Benton all the way!

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  5. [Anonymous is, I'm pretty sure, Monica emphasizing her point.]

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  6. Why is this so close? I don't know that I've liked Benton before, and I do like my Renaissance subjects, but I'm feeling the Benton love today.

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  7. Hey, I'm all for the Venetians, especially the new guy with the big book and the lizard. But I got to experience a whole room of Thomas Hart Benton murals at the Met last week, and I was completely wowed. Benton for me.

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  8. Lotto is really starting to grow on me! I vote for Tom Benton.

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  9. Why is this so close? Oh, it isn't. Benton racks up ten votes, Lotto only gets the one. It's Benton who will be taking on the Goldsworthy juggernaut next weekend in Fourth Round play.

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Voting in the Infinite Art Tournament? Awesome. And, please be aware that purely anonymous votes are not counted. You don't need to log in or use your real name, but you must identify yourself in some fashion for your vote to count.