The Brackets!

Tuesday, November 18, 2014

Infinite Art Tournament, Left Bracket Round Three TIEBREAKER: Arcimboldo v. Brown!

Here's the second half of the tiebreaker we started last Thursday.  Arcimboldo and Brown both won their first two matches, lost their third, and tied their fourth.  One of them is on the verge of a final loss; the other will return in a few months to face the winner of Jan Bruegel vs. Arthur Boyd.  It's gonna be great!


Giuseppe Arcimboldo
1527-1593
Italian








Ford Madox Brown
1821 - 1893
English
  • Defeated Marcel Broodthaers in a Round 1 contest that went down to the last vote. YOUR VOTE COUNTS!!!
  • Defeated Agnolo Bronzino in a Round 2 contest that also went down to the last vote. YOUR VOTE COUNTS!!!
  • Crushed by Pieter Bruegel in Round 3.
  • Tied with George Bellows in the Left Bracket Third Round. YOUR VOTE COUNTS!!!






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Vote for the artist of your choice in the comments, or any other way that works for you. Commentary and links to additional work are welcome. Polls open for at least one month past posting.

15 comments:

  1. I like them both, but I'm going for the wackiness of Arcimboldo.

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  2. I'm going to go with Arcimboldo, to be eventually bested by Jan Bruegel.

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  3. I'm kinda tired of him, but I'll say Arcimboldo anyway.

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  4. Honestly, I'd rather look at Brown at this point. Arcimboldo is a Johny One-Note. But, I still remember how delighted I was the first time I saw him, and that past me is casting my vote for him.

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  5. Brown, because I agree with everything Michael5000 says above except the part where I'm voting in the past.

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  6. Wow, Arcimboldo dominates Brown with a decisive 11-3 victory. That will put him against the winner of J.Bruegel/Boyd in the LB Third Round, while Brown loses two in a row and shuffles back to the studio.

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Voting in the Infinite Art Tournament? Awesome. And, please be aware that purely anonymous votes are not counted. You don't need to log in or use your real name, but you must identify yourself in some fashion for your vote to count.