Andrea del Sarto
1486-1530
Italian
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Antonello da Messina
unknown - 1479
Italian
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Faceoff #2: Appel v. Arp
Karel Appel
1921 - 2006
Dutch; worked internationally
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Jean Arp
1886 - 1966
German/French
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Vote for the two artists of your choice! Votes generally go in the comments, but have been known to arrive by email, by postcard, or in a sealed envelope.
Please note that you may vote only once in each faceoff. Opining that both of the artists in one of the two faceoffs is superior to the other is fine, but casting your votes for two artists in the same faceoff is not permissible.
25 comments:
DA MESSINA, and then APPEL because his first one makes me grin.
Da Messina 1779-1843 American?
You're messing with us.
da Messina
Apel
Good eye, Mrs.
I only like Arp
Wait... Loser's bracket? Are these guys playing back into the tournament? Or are you going to also have a backwards tournament determining who the worst artist of all time is? Either way, when in doubt I vote against the cupid picture and for... Apel
-Chuckdaddy
da Messina
Arp
da Messina and Arp
da Messina
Arp
I'm going to go with Antonello da Messina by a country mile, and then Apell because his first one makes me grin.
Messina, Apell
del Sarto and Appel.
By email, there's votes here for Antonio da Messina and Arp.
Da Messina and Appel.
da Messina, Appel, yes, indeed.
Anonymous, you need a name for your vote to count...
da Messina and Appel!
Messina and Appel.
I realize there's a tie glumping things up (By which, I mean making everything fantastically confusing), but can't this round be decided? It's not parallel to the tie (my way of looking at it).
No can do, Chuckdaddy. Until the Fra Angelico/Anguissola tangle is cleared up -- hopefully, to be frank, with them both winning through -- there's no opponent for Appel/Arp to play. It looks like it will be da Massina v. Archipenko, eventually, but there's no point kicking off THAT match because the winner will have to wait for the resolution of [Appel/Arp] v. whomever. In the meantime, I like having "#2/125" still active to remind me of the time before I realized that the tournament was going to have 1024 artists instead of 1000, before I realized that it was going to have 512 instead of 1024. And I also like knowing that it bugs you.
Then why did you advance the Archimboldo and Archipenko winner? And, how will
ties be worked out that happen outside of round one? I've been assuming (or maybe you told me) that we are waiting for a different same-round tie, and then a swap of matches will ensue. But I wouldn't put it past you to have something much more confusing up your sleeve.
Inexperience. It was my first tie, and I didn't realize that there was no point in closing down voting on it.
We are indeed waiting for another same-round tie. Let's say it's Clouet and Cornell (although it won't be): what would happen would be that the "upper" artist in each bracket (Fra Angelico and Clouet) would duke it out to advance on the "upper" bracket spot (ie, the winner would face Arcimboldo in the Third Round and the loser would face the winner of Appel/Arp). Anguissola would similarly go up against Cornell down there among the "C" artists.
For all that it sounds kind of arcane, it's a pretty reasonable tie breaker. Having said that, I like the way it makes possible sudden crazy sideways jumps on the brackets. Since I really like both the Fra and Anguissola, it's tempting to think of scenarios where I could use my vote (or withhold it) to clinch a tie between a pair of weaklings...
Sarto and Appel
Appel, haha - I can't stop looking at that first one
Alison thinks she can vote twice
And this antiquity of the tournament -- "Loser's Bracket" indeed -- finally drags to a close. In the end, Antonello da Messina wiped the floor with Andrea del Sarto, 12-2, while Appel dispatched Arp without too much ado, 10-5.
Voting closed!
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